cos 6 theta in terms of sin theta
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cos6θ
=cos2(3θ)
=1-2sin²3θ
=1-2(3sinθ-4sin³θ)²
=1-2(9sin²θ+16sin^6θ-24sin^4θ)
=1-18sin²θ+32sin^6θ-48sin^4θ
=cos2(3θ)
=1-2sin²3θ
=1-2(3sinθ-4sin³θ)²
=1-2(9sin²θ+16sin^6θ-24sin^4θ)
=1-18sin²θ+32sin^6θ-48sin^4θ
akshio:
cos in power of 6 theta in terms of sin theta i need it using demovire's theorem .........cos to the power of 6 theta
hey how did you get the keyboard with all these mathematical symbols? I also need it
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