Math, asked by jhad7376, 8 months ago

Cos 60 = 1-2sin ²30=2cos²- 30-1= cos²30 -sin²30

Answers

Answered by Anonymous
1

Answer:

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2cos2 60° + 3sin2 45° − 3sin2 30° + 2cos2 90°.

Solution:

We know that,

sin 45° = 1/√2 , cos 60° = 1/2

sin 30° = 1/2 and cos 90° = 0

Now,

2cos2 60° + 3sin2 45° − 3sin2 30° + 2cos2 90°

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