Cos 60 = 1-2sin ²30=2cos²- 30-1= cos²30 -sin²30
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Answer:
2cos2 60° + 3sin2 45° − 3sin2 30° + 2cos2 90°.
Solution:
We know that,
sin 45° = 1/√2 , cos 60° = 1/2
sin 30° = 1/2 and cos 90° = 0
Now,
2cos2 60° + 3sin2 45° − 3sin2 30° + 2cos2 90°
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