cos 60° ÷ 1 + sin60° = 1 ÷ sec 60° + tan 60°
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Hi ,
LHS = cos 60° / ( 1 + sin60° )
= 1/2 / ( 1 + √3 /2 )
= 1 / ( 2 + √3 )
RHS = 1/ ( sec60 + tan 60 )
= 1 / ( 2 + √3 )
Therefore ,
LHS = RHS
I hope this helps you.
:)
LHS = cos 60° / ( 1 + sin60° )
= 1/2 / ( 1 + √3 /2 )
= 1 / ( 2 + √3 )
RHS = 1/ ( sec60 + tan 60 )
= 1 / ( 2 + √3 )
Therefore ,
LHS = RHS
I hope this helps you.
:)
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