cos 65/sin25 + cos 32/sin 58 - sin28*sec62 + cosec^230
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Answers
Formulas used =
1.Sin A = Cos(90 - A) and vice versa
2.Cos A = 1/Sec A and vice versa
3.Cosec 30 = 2
⇒sin 65 + cos 32 - sin28.sec62 + cosec 30
--------- ----------
cos 25 sin 58
Formulas Used Below 1 and 2
⇒sin 65 + sin(90 - 32) - cos(90 - 28). 1 + cosec 30
--------------- ---------------- ---------
sin(90 - 25) sin 58 cos 62
⇒sin 65 + sin 58 - cos 62. 1 + cosec 30
--------- -------- --------
sin 65 sin 58 cos 62
=1 + 1 - 1 + 2 ------[Cosec 30 = 2]
=1 + 2
=3
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