Math, asked by manusinghinaya, 8 months ago

cos 65/sin25 + cos 32/sin 58 - sin28*sec62 + cosec^230
pls tell fast​

Answers

Answered by Anonymous
0

Formulas used  =  

1.Sin A = Cos(90 - A) and vice versa

2.Cos A = 1/Sec A and vice versa

3.Cosec 30 = 2

⇒sin 65  +  cos 32  -  sin28.sec62  + cosec 30

  ---------    ----------

  cos 25     sin 58

                                                 

Formulas Used Below 1 and 2

⇒sin 65  +     sin(90 - 32) -  cos(90 - 28).    1   + cosec 30

---------------    ----------------                            ---------      

sin(90 - 25)       sin 58                               cos 62    

⇒sin 65  + sin 58  - cos 62.  1    +   cosec 30

  ---------    --------                 --------        

  sin 65     sin 58              cos 62      

=1 + 1 - 1 + 2 ------[Cosec 30 = 2]

=1 + 2

=3

Hope u Understood

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