Question

Cos 68degree+sin 72 dergee = sin 22dergee + cot 18 dergee

Answer 1

i think ur question is wrong

Answer 2

Correct question is Cos68 + Sin72 = Sin22 + Cos18
Apply the formula:
$\sin(x) = \cos(90 - x) \\ and \\ \cos(y) = \sin(90 - y)$
Therefore
Cos68 + Sin72
=Sin(90-68) + Cos(90-72)
=Sin22 + Cos18