Math, asked by unique1man, 9 months ago

cos^6A+sin^6A=1/4(1+3cos²2A)

Answers

Answered by suji1319

1

Answer:

by ( a3 + b3 ) formula

---> (cos2A + sin2A ) (cos4A - cos2A. sin2A + sin4A)

---> ( sin4A + cos4A) - sin2A.cos2A

( therefore cos2A + sin2A = 1)

----> 1+3 sin2A.cos2A

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