Question

cos^6A + sin^6A = 1 - K sin^A cos^A? A where K =
(a) 4
(6)3
(c) 1
(d) 2​

Answer 1

Answer:

cos6α+sin6α+ksin22α=1

⇒(cos2α)3+(sin2α)3+ksin22α=1

⇒1−3sin2αcos2α+ksin22α=1

⇒1−43sin22α+ksin22α=1

⇒1+sin22α(k−43)=1

⇒k=43

HOPE IT WILL HELP YOU...