Question

cos 70°/Sin 20°+Cos 69°×Cosec 21°​

Answer 1

Answer:

sin(90° - θ) = cos θ cos (90° - θ) = sinθ tan(90° - θ) = cotθ cot(90° - θ) = tanθ sec(90° - θ) = cosecθ cosec(90° - θ) = secθ

Answer 2

Answer:

$\cos( \infty 99 \frac{32}{?} \times \frac{?}{?} )$