Math, asked by pkabindra2, 8 months ago

cos 70°/sin20°+cos59°/sin31°=8sin^2 30°​

Answers

Answered by angadsingh1709
1

Step-by-step explanation:

cos 70/sin20+cos59/sin31=8sin^2 30

cos(90-20)/sin20+cos(90-31)/sin31=8sin^2 30

=> sin20/sin20+sin31/sin31=8sin^2 30

=> 1+1=8(1/2)^2

=>2=8(1/4)

=>2=2

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