cos 80
______ +cos 59 cosec 31
sin 10
Answers
Answered by
0
Answer:
Answer:
\frac{cos80}{sin10}+cos59\cdot cosec31=2
sin10
cos80
+cos59⋅cosec31=2
Step-by-step explanation:
\frac{cos80}{sin10}+cos59\cdot cosec31
sin10
cos80
+cos59⋅cosec31
=\frac{cos(90-10)}{sin10}+cos59\cdot cosec(90-59)=
sin10
cos(90−10)
+cos59⋅cosec(90−59)
=\frac{sin10}{sin10}+cos59\cdot sec59=
sin10
sin10
+cos59⋅sec59
/*i)cos(90-A)=sinA
ii) cosec(90-A)=secA*/
=1+ 1=1+1
/* cosAsecA = 1 */
=2=2
Therefore,
\frac{cos80}{sin10}+cos59\cdot cosec31=2
sin10
cos80
+cos59⋅cosec31=2
•••♪
Step-by-step explanation:
plz follow me
and mark as brainlist
Similar questions