cos(90-a)= 0 then sin A+B =
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Answer:
cos 2b
Explanation:
cos (a+b) =0
=> cos (a+b) = cos 90
=> a+b = 90
=> a = 90- b
Now
sin(a+b)
= sin(90-b-b)
= sin(90-2b)
= cos 2b [as sin (90 - x) = cos x]
1THANK YOU
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