Math, asked by sharanappaganager7, 2 months ago

cos(90*-A)=0 then sin(A+B)= what​

Answers

Answered by Anonymous
4

Given :-

cos ( 90° - A ) = 0

To find :-

sin ( A + B )

Solution :-

→ cos ( 90° - A ) = 0

:: This means that sin A is also equal to 0

→ sin ( A ) = 0

:: Now use the following formula for sin ( A + B)

→ sin ( A + B ) = sin A cos B + cos A sin B

→ sin ( A + B ) = (0)( cos B ) + cos A sin B

→ sin ( A + B ) = cos A sin B

So the required answer is cos A sin B

Answered by shivaprasadvathare
1

Answer:

sinB = 0 answer is 0

Step-by-step explanation:

cos90=0

0-A=0 then a=0

sin(0+B)=sinb+sin0

then sinb

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