cos(90*-A)=0 then sin(A+B)= what
Answers
Answered by
4
Given :-
cos ( 90° - A ) = 0
To find :-
sin ( A + B )
Solution :-
→ cos ( 90° - A ) = 0
:: This means that sin A is also equal to 0
→ sin ( A ) = 0
:: Now use the following formula for sin ( A + B)
→ sin ( A + B ) = sin A cos B + cos A sin B
→ sin ( A + B ) = (0)( cos B ) + cos A sin B
→ sin ( A + B ) = cos A sin B
So the required answer is cos A sin B
Answered by
1
Answer:
sinB = 0 answer is 0
Step-by-step explanation:
cos90=0
0-A=0 then a=0
sin(0+B)=sinb+sin0
then sinb
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