Question

cos(90-A)=0 , value of sin(A+B) is ?​

Answer 1

Step-by-step explanation:

cos (90-A)=0

that is 90-A = cos~¹(0) = 90

so A = 0

now sin (A+B) = Sin (0+B)

= sin B

OR

COS (90-A) = 0

THAT IMPLIES....SIN(A)= 0

SIn (A+B ) = SinA . CosB + CosA . SInB

= 0. CosB + CosA .Sin B

= SinB