Question

cos(90-A). Sin(90-A)/tan(90-A)= sin²A

Answer 1

cos(90°-A).sin(90°-A)/tan(90°-A) 
= sinAcosA/cotA 
= sinAcosAtanA 
= sinAcosAsinA/cosA 
= sin^2A
I hope it help you

Answer 2

HEYA MATE, HERE IS UR ANSWER

We will use the following identities

Cos (90-A)=sinA

Sin (90-A)=cos A

Tan (90-A)=cot A

So let's start.....

$\frac{cos (90-A)×sin (90-A)}{tan (90-A)}$

= $\frac {sin A ×cos A}{cot A}$

=$\frac{Sin A×cos A}{\frac{Cos A}{sinA}}$

=$\frac {SinA×cos A×sinA}{cos A}$

=Sin A×sin A

=${Sin}^{2}A$

$\mathbb{Be\:Brainly}$