Question

cos (90-b)sin(c-a) + sin(90+a)cos(b+c) - sin(90-c)cos(a+b)​

Answer 1

Answer:

f to to do with the kids to the gym and then I will be in

Answer 2

Answer:

0

Step-by-step explanation

cos (90-b)sin(c-a) + sin(90+a)cos(b+c) - sin(90-c)cos(a+b

=sinB sin(c-a) + cosA cos(b+c) -cosC cos(a+b)

=sinB (sinCcosA-cosCsinA) + cosA (cosBcosC-sinBsinC) -cosC (cosAcosB-sinAsinB)

=sinBsinCcosA - sinAsinBcosC + cosAcosBcosC - sinBsinCcosA - cosAcosBcosC + sinAsinBcosC

=0 Zero. [they cancel each other]