Question

cos(90+theeta)sec(-theeta)tan(180-theeta)/ sec(360-theeta)sin(180+theeta)cot(90-theeta)

(◕ᴗ◕✿)(◔‿◔)

I need the answer of this question..​

Answer 1

Answer:

\frac{cos(90+ \alpha ).sec(- \alpha ).tan(180- \alpha )}{sec(360- \alpha ).sin(180+ \alpha ).cot(90- \alpha )}

sec(360−α).sin(180+α).cot(90−α)

cos(90+α).sec(−α).tan(180−α)

\frac{-sin \alpha .sec \alpha .-tan \alpha }{sec \alpha .-sin \alpha .tan \alpha }

secα.−sinα.tanα

−sinα.secα.−tanα

\frac{-sin \alpha. sec \alpha .tan \alpha }{sin \alpha. sec \alpha .tan \alpha }

sinα.secα.tanα

−sinα.secα.tanα

-1

Answer 2

Answer:

we know that.

cos(90°+◑)=(-sin◑)

sec(-◑) = sec◑

tan (180°-◑) = (-tan◑)

sec (360°-◑) = (sec◑)

sin (180°+◑) = (-sin◑)

cot (90°-◑) = tan◑

= (-sin◑) (sec◑) (-tan◑) /(sec◑) (-sin◑) (-tan◑)

= 1