Question

cos(90+theeta)sec(-theeta)tan(180-theeta)/ sec(360-theeta)sin(180+theeta)cot(90-theeta)


need answer ​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

we know that.

cos(90°+◑)=(-sin◑)

sec(-◑) = sec◑

tan (180°-◑) = (-tan◑)

sec (360°-◑) = (sec◑)

sin (180°+◑) = (-sin◑)

cot (90°-◑) = tan◑

$\frac{cos(90 + theta) \sec(theta) \tan(180 - theta) }{ \sec(360 - theta) \sin(180 + theta) - \cot(90 - theta) }$

$= \frac{( - sin \: theta)(sec \: theta)( - tan \: theta)}{(sec \: theta)( - sin \: theta)( - tan \: theta)}$

$= 1$