Question

cos(90-theta)tan(90-theta)=cos theta.​

Answer 1

Answer:

Sine and cosine — a.k.a., sin(θ) and cos(θ) — are functions revealing the shape of a right triangle. Looking out from a vertex with angle θ, sin(θ) is the ratio of the opposite side to the hypotenuse , while cos(θ) is the ratio of the adjacent side to the hypotenuse .

Answer 2

Answer:

Sin (90-theta )cos (90-theta) = tan theta / 1 + cot2 (90 – theta)

Let us start with LHS

sin(90-θ)cos(90-θ)

=cosθ . sinθ

Now let us solve RHS

tanθ/1+cot²(90-θ)

=tanθ/1+tan²θ

=tanθ/sec²θ

=sinθ/cosθ × cos²θ

=sinθcosθ

Now on solving LHS and RHS we get the same equation

Hence LHS= RHS

Hence Proved