Question

cos(90-thita)sec(90-thita)tan thita/cosec(90-thita) sin(90-thita) cot(90-thita)+tan(90-thita)/cot thita=2 prove the following​

Answer 1

Step-by-step explanation:

cos(90-theta)= sin(theta)

sec(90-theta)= cosec(theta)

sin(90-theta)=cos(theta)

tan(90-theta)=cot(theta)

cot(90-theta)=tan(theta)

cosec(90-theta)=sec(theta)

so now given that substituting in given equation

sin(theta)cosec(theta)tan(theta)/sec(theta)cos(theta)tan(theta)

+ cot(theta)/cot(theta)

tan(theta)/tan(theta)= 1

since cosec(theta)=1/sin(theta)

sec(theta)=1/cos(theta)

sin(theta)* 1/sin(theta)/

1/cos(theta)*cos(theta)

+ 1

1/1 +1= 2