Question

cos (90° - 0)÷1+ sin (90° - 0)+1+ sin (90° -0)÷cos (90°-0) = 2 cosec

0 means theta

I need correct answer​

Answer 1

[cos(90-@)/1+sin(90-@)] +[1+sin(90-@))/cos(90-@)]

[sin@/1+cos@] +[1+cos@/sin@]

rationalise sin@/1+cos@

we get

1-cos@/sin@

then

1-cos@/sin@ + 1+cos@/sin@

{1-cos@+1+cos@}/sin@

2/sin@

2cosec@.

hope it helpa

Answer 2

Answer:

sorry I can't so you please ask other person