Question

cos(90°-A) =0, then sin (a+b) =​

Answer 1

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We know that

● cos (90 - x) = sin x

● sin (x + y) = sin x • cos y + cos x • sin y

so,

⇒ cos (90 - A) = 0

⇒ sin A = 0 _______ (1)

then,

→ sin (A + B)

→ sin A • cos B + cos A • sin B

Putting value of (1)

→ 0 • cos B + cos A • sin B

→ cos A • sin B ________ (2)

Since,

⇒ sin A = 0

⇒ sin A = sin 0°

⇒ A = 0

Now,

= cos A • sin B

= cos 0° • sin B

= 1 • sin B

= sin B

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