Cos(90°-A)/sin A + sin(90°-A)/cos A=2
Answers
Answered by
1
We know, cos(90 - ∅) = sin∅
sin(90 - ∅) = cos∅
Hence,
cos(90 - A)/sinA + sin(90 - A)/cosA
Applying formula, we get
=> sinA/sinA + cosA/cosA
=> 1 + 1
=> 2
sin(90 - ∅) = cos∅
Hence,
cos(90 - A)/sinA + sin(90 - A)/cosA
Applying formula, we get
=> sinA/sinA + cosA/cosA
=> 1 + 1
=> 2
Answered by
2
Cos (90°-A)/SinA + Sin(90°-A)/Cos A
Similar questions