cos(90°-theta)cos0/tan0 + cos^2(90°-theta) = 1
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Answer:
sin(90
o
−θ)=cosθ, cos(90
o
−θ)=sinθ,
cosec(90
o
−θ)=secθ, cot(90
o
−θ)=tanθ,
sec(90
o
−θ)=cosecθ, tan(90
o
−θ)=cotθ
∴
cosec(90−θ)sin(90−θ)cot(90−θ)
cos(90−θ)sec(90−θ)tanθ
+
cotθ
tan(90−θ)
∴
sin(90−θ)
1
×sin(90−θ)×tanθ
sinθ×
cos(90−θ)
1
×tanθ
+
cotθ
cotθ
=
cosθ
1
×cosθ
sinθ×
sinθ
1
+1
=1+1=2
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