Question

Cos 9x-cos 5x÷sin17x- sin3x= -sin2x÷cos10x

Answer 1

Answer:

cos9x- cos5x / sin17x-sin3x =

sin2x/cos 10x

LHS:

=> {2sin (9x+5x)/2.sin(9x-5x)/2}/{2cos(17x+3x) /2.sin (17x-3x) /2}

=> 2sin7x.sin2x/2cos10xsin7x

=> 2sin2x/2cos10x

=> sin2x/cos10x

hence LHS = RHS.

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