Cos A/1+sin A + 1+sin A/cos A=2sec A
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Step-by-step explanation:
let LHS,
cos A/1+sin A +1+sinA/cosA
after cross multiplication we get
cos^2A+(1+sinA)^2/cosA(1+sinA)
expand(1+sinA)^2=1+sin^2+2sinA
cos^2A+1+sin^2A+2sinA/cosA(1+sinA)
cos^2A =1-sin^2A using identity
therefore
1-sin^2A+1+sin^2+2sinA/cosA(1+sinA)
2+2sinA/cosA(1+sinA)
2(1+sinA)/cosA(1+sinA)
2/cosA.
secA=1/cosA
2secA
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