Math, asked by aankit593, 1 year ago

Cos a /1+sin a=1-sin a/cosa

Answers

Answered by Anonymous
3
Divide LHS by cosA,

tanA+secA−1/tanA−secA+1tanA+secA−1/tanA−secA+1

=tanA+secA−(sec2A−tan2A)/tanA−secA+1=tanA+secA−(sec2A−tan2A)/tanA−secA+1

=tanA+secA−[(tanA+secA)(secA−tanA)]/tanA−secA+1=tanA+secA−[(tanA+secA)(secA−tanA)]/tanA−secA+1

=(tanA+secA)1−secA+tanA/1−secA+tanA=(tanA+secA)1−secA+tanA/1−secA+tanA

=tanA+secA=tanA+secA

=(secA+tanA)(secA−tanA)/secA−tanA=(secA+tanA)(secA−tanA)/secA−tanA

=(sec2A−tan2A)/secA−tanA=(sec2A−tan2A)/secA−tanA

=1/secA−tanA=1/secA−tanA

R.H.S=L.H.SR.H.S=L.H.S

Hence proved



MARK BRAINLIEST..

aankit593: This is not correct answer
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