Question

Cos A/1+sin A + 1+sinA /cosA=2secA

Answer 1

Answer:(cos²a+1+sin²a+2sina) /

              =  ( 2+2sina) / (1+sina)(cosa)    [ as sin²a+ cos²a =1 ]

           =  2(1+sina) /  (1+sina)(cosa)       [ take 2 as common]

            =2/cosa

               = 2seca

Step-by-step explanation:

Answer 2

Answer:

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