COS A + 1 +SIN A = 2 SEC A SOLVE THIS TRIGNOMENTORY RATIO
1+SIN A COS A
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2cos²A/2+2sinA/2cosA/2
2cosA/2{cosA/2+sinA/2}
2cosA/2{cosA/2+sinA/2}
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COS A 1 + SIN A
--------- + -------------- cross multiply denominators & numerators
1 + SIN A COS A
cos² A + 1 + Sin² A 2
----------------------------- = ------------------ = 2 Sec A given
(1+sin A) Cos A (1 + sin A) cos A
=> 1 + Sin A = 1 => A = 0 or 2π cos A Sec A = 1
--------- + -------------- cross multiply denominators & numerators
1 + SIN A COS A
cos² A + 1 + Sin² A 2
----------------------------- = ------------------ = 2 Sec A given
(1+sin A) Cos A (1 + sin A) cos A
=> 1 + Sin A = 1 => A = 0 or 2π cos A Sec A = 1
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