Math, asked by Anand5093, 10 months ago

Cos A/1+ sin A+ tan A= sec A

Answers

Answered by sandy1816

2

Step-by-step explanation:

cosA/1+sinA +tanA

=cosA/1+sinA +sinA/cosA

=cos²A+sinA(1+sinA)/(1+sinA)cosA

=cos²A+sinA+sin²A/(1+sinA)cosA

=1+sinA/(1+sinA)cosA

=1/cosA

=secA

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