Question

cos A/1+sinA + 1+sinA/cosA =2 Se A prove this identity ​

Answer 1

Answer:

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Step-by-step explanation:

cosA/(1+sinA) + (1+sinA)/cosA

[cos²A + (1+sinA)²]/(1+sinA)cosA

[cos²A + 1 + sin²A + 2sinA]/(1+sinA)cosA

sin²A + cos²A = 1

[2 + 2sinA]/(1+sinA)cosA

2(1+sinA)/(1+sinA)cosA

2/cosA

2secA