Question

cos a/1-tan a + sin2 a/cos a -sin a =sin a +cos a​

Answer 1

Step-by-step explanation:

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tq for points

sorry !!!!!!

Answer 2

Answer:

I think this question is wrong

The correct question will be cos a/1-tan a - sin2 a/cos a -sin a =sin a +cos a​

Step-by-step explanation:

LHS = $\frac{cos A}{1 - tan A} - \frac{sin^2 A}{cos A - sin A}$

$\frac{cos A}{1 - \frac{sin A}{cos A} } + \frac{sin^2 A}{sin A - cos A}$

$\frac{cos A}{\frac{cos A - sin A}{cos A} } + \frac{sin^2 A}{sin A - cos A}$

$\frac{cos^2 A}{cos A-sinA} + \frac{sin^2A}{sinA-cos A}$

$\frac{cos^2 A}{cos A-sinA} - \frac{sin^2A}{cosA-sin A}$

$\frac{cos^2A-sin^2A}{cosA-sinA\\}$

$\frac{(cosA+sinA)(cosA-sinA)}{(cosA-sinA)}$

Therefore, cos A + sin A = RHS (PROVED)