Question

cos A=12/13, then sin A=--------​

Answer 1

Answer:

5

Step-by-step explanation:

COS A = BASE/HYPOTENUSE

= 12/13

GIVEN............BASE = 12

HYPOTENUSE=13

TO FIND........PERPENDICULAR=?

SOLUTION:-

BY USING PYTHAGORAS THEORM

H² = P²+B²

13²= P²+12²

169=P²+ 144

169-144= P²

25 = P²

√25 = P

5 = P

(HENCE PROVED)

Answer 2

Step-by-step explanation:

sin2A+cos2A=1

sin2A+(12/13)2=1

sin2A+(144/169)=1

sin2A+144=1×169

sin2A+144=169

sin2A=169-144

sin2A=25

sinA=root of 25

sinA=5