Math, asked by swati2006, 1 year ago

cos a=5/13 evaluate sin a-cos a /2 tan a

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Answered by Anonymous
2
hello Swati here is your answer by Sujeet,


that's all
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swati2006: thanx
Answered by ishwarsinghdhaliwal
3

cosA =  \frac{5}{13}  \:  \\ <br />So, sinA =  \frac{12}{13}   \ \\  \: tanA =  \frac{12}{5}  \\  cotA =  \frac{5}{12} <br /> \\   \frac{(sinA - cosA)}{2tanA}  \\ <br />= \frac{ ( \frac{12}{13}  -  \frac{5}{13} )}{(2× \frac{12}{5} )} <br />=  \frac{7}{13} × \frac{5}{24}  \: <br />=  \frac{35}{312}

swati2006: thanx
ishwarsinghdhaliwal: wlc
ishwarsinghdhaliwal: wlc
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