Math, asked by abcd32481, 10 months ago

cos (A+B) = 1/2 and sin (A– B)= 1/2 <A+B<90° and A-B>0°. What are
the values of A And B​

Answers

Answered by saritasrivastava
1

Answer:

cos 60 =1/2

sin 30 =1/2

a+b=60

a-b=30

a+b+a-b=60+30

2a=90

=>a =45

=>b =15

Answered by nessintin12
0

Step-by-step explanation:

cos(A+B)=1/2

sin(A-B)=1/2

NOW WE NEED TO CHECK THAT FOR WHAT VALUE OF COS IS THE VALUE 1/2.

CLEARLY ITS 60° AND FOR SIN IT IS 30°

A+B=60

A-B=30

ON ADDING THE EQUATIONS WE GET,

2A=90

=)A=45°

putting the value of A in any of the equations we get,

B=15°

HOPE IT HELPS, PLZ MARK BRAINLIEST

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