Question

cos A + B/2 = sin C/2

please give only answers​

Answer 1

Step by step explanation

Let, A, B & C are the angles of a triangle.

So, we can write,

A + B + C = 180°

Or, A + B = 180° - C

Dividing both sides by 2. We get,

A + B/2 = 180° - C/2

Operating 'cos' on both sides. We get,

cos ( A + B/2) = cos (90° - C/2) [ Note : In RHS C is only divided by 2 not 90°)

Therefore, cos ( A + B/2) = sin C/2

Answer 2

Answer:

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