cos (a- b) = √3/2; sin ( a+ b) = √3/2 find a and b( a+ b) and ( a- b ) are acute Angeles
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Cos(a-b)=√3/2
=>a-b= Cos^-1(√3/2)
=>a-b= 30 -------- 1
Now,
Sin(a+b)=√3/2
=>a+b=Sin^-1(√3/2)
=>a+b=60. ---------2
From 1 and 2,
a-b+a+b= 30+60
=>2a=90
=>a=45°
Similarly, b=15°
=>a-b= Cos^-1(√3/2)
=>a-b= 30 -------- 1
Now,
Sin(a+b)=√3/2
=>a+b=Sin^-1(√3/2)
=>a+b=60. ---------2
From 1 and 2,
a-b+a+b= 30+60
=>2a=90
=>a=45°
Similarly, b=15°
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