Cos(a+b)=cosA×Cos B - sin A × sin B (where A is 60 and B is 30 )
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ashrafzeeshan90:
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Here is your answer :-
cos(A +B) = cos A × cos B - sin A × sin B ---(1)
It is given A = 60° and B = 30 °
Put these values in (1)
cos ( 60+30) = cos 60° × cos 30° - sin 60° × sin 30°
cos 90° = 1/2 × √3/2 - √3/2 × 1/2
cos90° = √3/4 - √3/4
cos 90° = 0
Hope it helps u ..mark as brainliest answer
cos(A +B) = cos A × cos B - sin A × sin B ---(1)
It is given A = 60° and B = 30 °
Put these values in (1)
cos ( 60+30) = cos 60° × cos 30° - sin 60° × sin 30°
cos 90° = 1/2 × √3/2 - √3/2 × 1/2
cos90° = √3/4 - √3/4
cos 90° = 0
Hope it helps u ..mark as brainliest answer
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