cos(A-B) /cosAcosB=tanA+cotB
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Answer:
sin(a+b) / cosAcosB = tan A + tan B
sin(a+b) = sincosB + cossinB ( identity )
sin(a+b) / cosAcosB = ( sinAcosB + cosAsinB )/ (cosAcosB)
= sinAcosB/ cosAcosB + cosAsinB/ cosAcosB
= sinA/ cosA + sinB/ cosB
= tanA + tanB
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Answered by
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Answer:
= cosA cosB+sinA sinB/cosA sinB
= cosA cosB/ cosA sinB+ sinB/ cos sinB
= cotB+ tanA
= tanA+ cotB
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