Math, asked by darshan2950, 11 months ago

Cos A + B into Cos A minus b​

Answers

Answered by aroranishant799
1

Ques. cos(A+B) cos(A−B) is equal to.

Answer:

Therefore, the required answer is cos(A+B) cos(A-B) = cos^{2} A-sin^{2}B.

Step-by-step explanation:

Concept:

There are six popular trigonometric functions for an angle. Sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant (cosec) are their respective names and acronyms. The three main trigonometry functions are sine, cosine, and tangent, while the other three are cotangent, secant, and cosecant. Equations involving trigonometric functions that hold true for all possible values of the variables are known as trigonometric identities.

Formulas used:

cos(A+B)= cosAcosB-sinAsinB

cos(A-B)= cosAcosB+sinAsinB

Given:

cos(A+B) cos(A-B)

To find:

We have to find the value of cos(A+B) cos(A-B).

Solution:

It is given that,

cos(A+B) cos(A-B)

=(cosAcosB-sinAsinB)(cosAcosB+sinAsinB)

=cos^{2} Acos^{2}B-sin^{2}Asin^{2}B

=cos^{2} A(1- sin^{2}B)-(1-cos^{2}A)-sin^{2}B

=cos^{2} A-sin^{2}B

Hence, the required answer is cos^{2} A-sin^{2}B.

#SPJ3

Answered by hemakumar0116
0

Answer:

cos2A - sin2B.

Step-by-step explanation:

Ques. cos(A+B) cos(A-B)

Answer:

Therefore, the required answer is cos(A+B)cos(A-B) = cos A- sin B

There are six popular trigonometric functions for an angle. Sine (sin), cosine ( cos), tangent (tan), cotangent (cot), secant (sec), and cosecant (cosec) are their respective names and acronyms. The three main trigonometry functions are sine, cosine, and tangent, while the other three are cotangent, secant, and cosecant. Equations involving trigonometric functions that hold true for all possible values of the variables are known as trigonometric identities. Formulas used:

cos(A+B)= cos Acos B-sinAsinB

cos (A-B)=cos Acos B+ sin AsinB

Given:

cos (A+B)cos(A-B)

To find:

We have to find the value of cos(A+B)cos(A-B).

Solution:

It is given that,

cos(A+B)cos(A-B)

= (cos Acos B-sin Asin B) (cos AcosB+ sin AsinB)

=cos2 Acos2 B- sin² Asin2B

=cos2A(1-sin2B)-(1-cos2A) - sin²B

=cos A-sin2 B

Hence, the required answer is cos2A - sin2B.

cos2A - sin2B.

Is the correct answer of this question.

#SPJ3

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