Question

cos (A-B)= under root 3/2
cos (A+B)= 1/2
find A and B​

Answer 1

Answer:

cos(A-B)=underroot3/2

cos(A-B)=cos30

A-B=30........................................1

cos(A+B)=1/2

cos(A+B)=cos60

(A+B)=60.....................................2

subtract first equation from second equation

A+B-A+B=60-30

2B=30

B=30/2

B=15

putting b = 15 in first equation

A-B=30

A-15=30

A=30+15

A=45

Answer 2

Answer:

A=45 an B=15

Step-by-step explanation:

cos(A+B) =1/2 cos(A-B) =√3/2

cos(A+B) =cos60 cos(A-B) =cos30°

both cos get ❌ both cos get ❌

u get then u get

A+B=60-----1 A-B=30-----2

from eq 1 and 2, we get

A+B=60

+ A-B= 30

_______

2A=90

A=90/2

A=45.........

A+B=60

45+B=60

B=60-45

B=15........

I think this will be helpful to u..........