cos a by 1plus sin a plus 1plus 1plus cos a is equal to 2sec a
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cos A = AB/AC
SIN A = BC/ AC
According to the question,
(AB/AC)/(BC/AC)+1+1+AB/AC
2+AC/AB ....(SEC=AC/AB)
2 AB/AC = 2 AB/AC
SIN A = BC/ AC
According to the question,
(AB/AC)/(BC/AC)+1+1+AB/AC
2+AC/AB ....(SEC=AC/AB)
2 AB/AC = 2 AB/AC
lekha86:
i did not understand
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