Question

cos A cos 2A cos 2 ^ 2A cos 2 ^ 3A. . . . . cos 2 ^ n - 1 A =​

Answer 1

Answer:

$\huge\pink{\boxed{\blue{\boxed{ \purple{ \boxed{{\pink{Answer}}}}}}}} \\ \large\pink{\boxed{\blue{\boxed{ \purple{ \boxed{{\pink{Your~answer↓}}}}}}}} \\ \small\bold\red{question \: from \: trigonometry} \\ cos A \: cos 2A \: cos 2 ^ 2A \: cos 2 ^ 3A. . . . . cos {2}^{n - 1} A = \frac{sin {2}^{n} A}{ {2}^{n} sinA}$

Answer 2

Answer:

this is correct.....................