Cos A -cos 3A-cos 5A + cos 7A / sin A-sin 3A + sin 5A-sin 7A = tan 2A
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Step-by-step explanation:
(cosA+cos7A)-(cos5A+cos3A)/ (sinA-sin7A)+(sin5A-sin3A)
=2cos4Acos3A-2cos4AcosA/ 2cos4Asin(-3A)+2cos4AsinA
=2cos4Acos3A-2cos4AcosA/ 2cos4AsinA-2cos4Asin3A
=cos3A-cosA/sinA-sin3A
=-2sin2AsinA/2cos2Asin(-A)
=-2sin2AsinA/-2cos2AsinA
=sin2A/cos2A
=tan2A
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Step-by-step explanation:
clear answer contains in below picture
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