Question

cos A + cos²A=1 then sin²A+ sin⁴A=?​

Answer 1

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$Gɪᴠᴇɴ = \: cos A + cos²A=1$

$Tᴏ \: Fɪɴᴅ = sin²A+ sin⁴A$

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$cos A + cos²A=1$

$\: \: \: \: \: cos A =1 - cos²A \: \: =>(1)$

$\: \: \: \: \: \ \: \: cos A = sin²A \: \: =>(2)$

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$sin²A+ sin⁴A$

$Fʀᴏᴍ \: ᴇϙᴜᴀᴛɪᴏɴ \: (1) \: ᴀɴᴅ \: (2); \: Wᴇ \: ɢᴇᴛ,$

$= cos A + {(cosA)}^{2}$

$= cos A + cos²A$

$= 1$

Hορє Iτ Hєℓρѕ Yου!

Answer 2

Step-by-step explanation:

cosA+cos²A=

: cos A =1 - cos²A =>(1)cosA=1−cos²A=>(1)

: cos A = sin²A =>(2) cosA=sin²A=>(2)

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sin²A+ sin⁴Asin²A+sin⁴A

Fʀᴏᴍ ᴇϙᴜᴀᴛɪᴏɴ ᴀɴᴅ Wᴇ ɢᴇᴛ,Fʀᴏᴍᴇϙᴜᴀᴛɪᴏɴ(1)ᴀɴᴅ(2);Wᴇɢᴇᴛ,

= cos A + {(cosA)}^{2}=cosA+(cosA)

2

= cos A + cos²A=cosA+cos²A

= 1