Cos A Cot A / 1 - Sin A = 1 + cosec A
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YOUR QUESTION.:
cosAcotA1−sinA=1+cosecA
I THINK YOU HAVE DONE SOME TYPING MISTAKE.
Answer for the question:
cosAcotA1−sinA=1+cosecA
Take,
LHS=cosAcotA1−sinA
=cosA(cosAsinA)1−sinA...→[as,cotA=cosAsinA]
=cos2AsinA(1−sinA)...→[where,cos2A=1−sin2A]
=(1−sin2A)sinA(1−sinA)
=(1−sinA)(1+sinA)sinA(1−sinA)
=1+sinAsinA
=1sinA+sinAsinA
=cosecA+1
=RHS
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