Math, asked by sainimahima173, 9 months ago

Cos A (I+ cotA) + sin A(1+ tan A) = sec A+CosecA​

Answers

Answered by yashaswini3679
12

Step-by-step explanation:

LHS = sin A(1+ tan A)+ cos A(1 + cot A)

= sin A + sin^2 A/ cos A + cos A + cos^2 A/ sin A

= sin A + cos A + [sin^3 A + cos^3 A]/sin A cos A

=[ sin^2 A cos A + cos^2 A sin A + sin^3 A + cos^3 A]/sin A cos A

= [ sin^2 A cos A +cos^3 A + cos^2 A sin A + sin^3 A]/sin A cos A

= [cos A (sin^2 A + cos^2 A) + sin A (sin^2 A + cos^2 A)]/sin A cos A

= [cos A +sin A]/sin A cos A

= (1/sin A) + (1/cos A)

= cosec A + sec A = RHS.

Hence, proved.

HOPE THIS ANSWER HELPS YOU ✍✍....

Similar questions