Question

cos A is equal to 2 by 3 then find the value of 2 tan square A + 9​

Answer 1

Answer:

Step-by-step explanation:

Let theta be 'A'

Given=> cosA = 2/3

= base/hypotenous

Perpendicular = √(3)² - (2)²

= √9 - 4

= √5

secA = hypogenous/base = 3/2

tanA = perpendicular/base

= √5/2

So,

=> 2sec²A + 2tan²A - 9

=> 2(3/2)² + 2(√5/2)² - 9

=> (2×9)/4 + (2×5)/4 - 9

=> 9/2 + 5/2 - 9

=> (9 + 5)/2 - 9

=> 14/2 - 9

=> 7 - 9

=> -2. . Answer