cos A is equals to b by a then find the value of 2 sec a
+ 1 by Cos A + 2
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(2secA+1)/(CosA+2)
now cosA=b/a
secA=a/b
substituting above values
[2(a/b)+1]/[(b/a)+2]
=[(2a+b)/b]/[(b+2a)/a]
=[(2a^2+ab)]/[(b^2+2ab)]
Hope it helps
:)
now cosA=b/a
secA=a/b
substituting above values
[2(a/b)+1]/[(b/a)+2]
=[(2a+b)/b]/[(b+2a)/a]
=[(2a^2+ab)]/[(b^2+2ab)]
Hope it helps
:)
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