Cos a minus sin a + 1 upon Cos a + sin a minus 1 equals to Cos secant a + cot a
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Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
we have to prove ( cosA - sinA + 1 ) / ( cosA + sinA - 1 ) = cosecA + cotA
left hand side = ( cosA - sinA + 1 ) / ( cosA + sinA - 1 )
= [ sinA (cosA-sinA+1) ] / [ sinA (cosA+sinA-1) ]
= ( sinA cosA - sin²A + sinA ) / sinA ( cosA + sinA - 1 )
= [ sinA cosA + sinA - ( 1 - cos²A ) ] / sinA ( cosA + sinA - 1 )
= [ sinA (cosA+1) - (1-cosA) (1+cosA) ] / sinA (cosA+sinA-1)
= [(1+cosA) (sinA+cosA-1) ] / sinA (cosA+sinA-1)
= ( 1 + cosA ) / sinA
= ( 1/sinA) + (cosA/sinA)
= cosecA + cot A
then (cosA - sinA + 1 ) / ( cosA + sinA - 1 ) = cosecA + cotA (proved)
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