cos a ÷ sec a- tan a = 1 + sina a
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HEY MATE LET ME PROOVE YOUR ANSWER......
WE ARE GIVEN THAT: (sec A+tan A)(1-sinA)
=(1/cos A + sin A/cos A)(1-sinA)
=[(1+sinA)/cosA](1-sinA)
=(1+sinA)(1-sinA)/cosA
=(1-sin^2 A)/cosA
=(cos^2 A)/cos A
=cos A
Hence proved
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